Problem
https://leetcode.com/problems/running-sum-of-1d-array/?envType=study-plan&id=level-1
Given an array nums. We define a running sum of an array as runningSum[i] = sum(nums[0]…nums[i]).
Example
Input: nums = [1,2,3,4]
Output: [1,3,6,10]
Explanation: Running sum is obtained as follows: [1, 1+2, 1+2+3, 1+2+3+4].
Solution
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class Solution {
public:
vector<int> runningSum(vector<int>& nums) {
int len = nums.size();
std:vector<int> ret;
int tmp = 0;
for (int i = 0; i< len; i++) {
ret.push_back(tmp + nums[i]);
tmp = ret[i];
}
return ret;
}
};